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10(b+5)=5(b)
We move all terms to the left:
10(b+5)-(5(b))=0
determiningTheFunctionDomain 10(b+5)-5b=0
We add all the numbers together, and all the variables
-5b+10(b+5)=0
We multiply parentheses
-5b+10b+50=0
We add all the numbers together, and all the variables
5b+50=0
We move all terms containing b to the left, all other terms to the right
5b=-50
b=-50/5
b=-10
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