10(b-2)-(8-2b)=-28

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Solution for 10(b-2)-(8-2b)=-28 equation:


Simplifying
10(b + -2) + -1(8 + -2b) = -28

Reorder the terms:
10(-2 + b) + -1(8 + -2b) = -28
(-2 * 10 + b * 10) + -1(8 + -2b) = -28
(-20 + 10b) + -1(8 + -2b) = -28
-20 + 10b + (8 * -1 + -2b * -1) = -28
-20 + 10b + (-8 + 2b) = -28

Reorder the terms:
-20 + -8 + 10b + 2b = -28

Combine like terms: -20 + -8 = -28
-28 + 10b + 2b = -28

Combine like terms: 10b + 2b = 12b
-28 + 12b = -28

Add '28' to each side of the equation.
-28 + 28 + 12b = -28 + 28

Combine like terms: -28 + 28 = 0
0 + 12b = -28 + 28
12b = -28 + 28

Combine like terms: -28 + 28 = 0
12b = 0

Solving
12b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '12'.
b = 0

Simplifying
b = 0

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