10(b-3)=-28

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Solution for 10(b-3)=-28 equation: 



10(b-3)=-28

We move all terms to the left:

10(b-3)-(-28)=0

We add all the numbers together, and all the variables

10(b-3)+28=0

We multiply parentheses

10b-30+28=0

We add all the numbers together, and all the variables

10b-2=0

We move all terms containing b to the left, all other terms to the right

10b=2

b=2/10

b=1/5

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