10(b-8)=-80

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Solution for 10(b-8)=-80 equation: 



10(b-8)=-80

We move all terms to the left:

10(b-8)-(-80)=0

We add all the numbers together, and all the variables

10(b-8)+80=0

We multiply parentheses

10b-80+80=0

We add all the numbers together, and all the variables

10b=0

b=0/10

b=0

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