10(c+31/5)=-102

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Solution for 10(c+31/5)=-102 equation: 



10(c+31/5)=-102

We move all terms to the left:

10(c+31/5)-(-102)=0

We add all the numbers together, and all the variables

10(+c+31/5)-(-102)=0

We add all the numbers together, and all the variables

10(+c+31/5)+102=0

We multiply parentheses

10c+102+31/5*10=0

We multiply all the terms by the denominator


10c*5*10+31+102*5*10=0

We add all the numbers together, and all the variables

10c*5*10+5131=0

Wy multiply elements

500c*1+5131=0

Wy multiply elements

500c+5131=0

We move all terms containing c to the left, all other terms to the right

500c=-5131

c=-5131/500

c=-10+131/500

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