10(c-1)=2(2c-5)

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Solution for 10(c-1)=2(2c-5) equation:


Simplifying
10(c + -1) = 2(2c + -5)

Reorder the terms:
10(-1 + c) = 2(2c + -5)
(-1 * 10 + c * 10) = 2(2c + -5)
(-10 + 10c) = 2(2c + -5)

Reorder the terms:
-10 + 10c = 2(-5 + 2c)
-10 + 10c = (-5 * 2 + 2c * 2)
-10 + 10c = (-10 + 4c)

Add '10' to each side of the equation.
-10 + 10 + 10c = -10 + 10 + 4c

Combine like terms: -10 + 10 = 0
0 + 10c = -10 + 10 + 4c
10c = -10 + 10 + 4c

Combine like terms: -10 + 10 = 0
10c = 0 + 4c
10c = 4c

Solving
10c = 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
10c + -4c = 4c + -4c

Combine like terms: 10c + -4c = 6c
6c = 4c + -4c

Combine like terms: 4c + -4c = 0
6c = 0

Divide each side by '6'.
c = 0

Simplifying
c = 0

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