10(c-3)+6=4+c-28

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Solution for 10(c-3)+6=4+c-28 equation: 


Simplifying
10(c + -3) + 6 = 4 + c + -28

Reorder the terms:
10(-3 + c) + 6 = 4 + c + -28
(-3 * 10 + c * 10) + 6 = 4 + c + -28
(-30 + 10c) + 6 = 4 + c + -28

Reorder the terms:
-30 + 6 + 10c = 4 + c + -28

Combine like terms: -30 + 6 = -24
-24 + 10c = 4 + c + -28

Reorder the terms:
-24 + 10c = 4 + -28 + c

Combine like terms: 4 + -28 = -24
-24 + 10c = -24 + c

Add '24' to each side of the equation.
-24 + 24 + 10c = -24 + 24 + c

Combine like terms: -24 + 24 = 0
0 + 10c = -24 + 24 + c
10c = -24 + 24 + c

Combine like terms: -24 + 24 = 0
10c = 0 + c
10c = c

Solving
10c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
10c + -1c = c + -1c

Combine like terms: 10c + -1c = 9c
9c = c + -1c

Combine like terms: c + -1c = 0
9c = 0

Divide each side by '9'.
c = 0

Simplifying
c = 0

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