10(c-3)+7=6+c-29

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Solution for 10(c-3)+7=6+c-29 equation: 


Simplifying
10(c + -3) + 7 = 6 + c + -29

Reorder the terms:
10(-3 + c) + 7 = 6 + c + -29
(-3 * 10 + c * 10) + 7 = 6 + c + -29
(-30 + 10c) + 7 = 6 + c + -29

Reorder the terms:
-30 + 7 + 10c = 6 + c + -29

Combine like terms: -30 + 7 = -23
-23 + 10c = 6 + c + -29

Reorder the terms:
-23 + 10c = 6 + -29 + c

Combine like terms: 6 + -29 = -23
-23 + 10c = -23 + c

Add '23' to each side of the equation.
-23 + 23 + 10c = -23 + 23 + c

Combine like terms: -23 + 23 = 0
0 + 10c = -23 + 23 + c
10c = -23 + 23 + c

Combine like terms: -23 + 23 = 0
10c = 0 + c
10c = c

Solving
10c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
10c + -1c = c + -1c

Combine like terms: 10c + -1c = 9c
9c = c + -1c

Combine like terms: c + -1c = 0
9c = 0

Divide each side by '9'.
c = 0

Simplifying
c = 0

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