10(c-4)+7=2+c-35

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Solution for 10(c-4)+7=2+c-35 equation: 



10(c-4)+7=2+c-35

We move all terms to the left:

10(c-4)+7-(2+c-35)=0

We add all the numbers together, and all the variables

10(c-4)-(c-33)+7=0

We multiply parentheses

10c-(c-33)-40+7=0

We get rid of parentheses

10c-c+33-40+7=0

We add all the numbers together, and all the variables

9c=0

c=0/9

c=0

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