10(c-5)+4=2+c-48

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Solution for 10(c-5)+4=2+c-48 equation: 


Simplifying
10(c + -5) + 4 = 2 + c + -48

Reorder the terms:
10(-5 + c) + 4 = 2 + c + -48
(-5 * 10 + c * 10) + 4 = 2 + c + -48
(-50 + 10c) + 4 = 2 + c + -48

Reorder the terms:
-50 + 4 + 10c = 2 + c + -48

Combine like terms: -50 + 4 = -46
-46 + 10c = 2 + c + -48

Reorder the terms:
-46 + 10c = 2 + -48 + c

Combine like terms: 2 + -48 = -46
-46 + 10c = -46 + c

Add '46' to each side of the equation.
-46 + 46 + 10c = -46 + 46 + c

Combine like terms: -46 + 46 = 0
0 + 10c = -46 + 46 + c
10c = -46 + 46 + c

Combine like terms: -46 + 46 = 0
10c = 0 + c
10c = c

Solving
10c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
10c + -1c = c + -1c

Combine like terms: 10c + -1c = 9c
9c = c + -1c

Combine like terms: c + -1c = 0
9c = 0

Divide each side by '9'.
c = 0

Simplifying
c = 0

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