10(c-6)+4=2+c-58

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Solution for 10(c-6)+4=2+c-58 equation: 


Simplifying
10(c + -6) + 4 = 2 + c + -58

Reorder the terms:
10(-6 + c) + 4 = 2 + c + -58
(-6 * 10 + c * 10) + 4 = 2 + c + -58
(-60 + 10c) + 4 = 2 + c + -58

Reorder the terms:
-60 + 4 + 10c = 2 + c + -58

Combine like terms: -60 + 4 = -56
-56 + 10c = 2 + c + -58

Reorder the terms:
-56 + 10c = 2 + -58 + c

Combine like terms: 2 + -58 = -56
-56 + 10c = -56 + c

Add '56' to each side of the equation.
-56 + 56 + 10c = -56 + 56 + c

Combine like terms: -56 + 56 = 0
0 + 10c = -56 + 56 + c
10c = -56 + 56 + c

Combine like terms: -56 + 56 = 0
10c = 0 + c
10c = c

Solving
10c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
10c + -1c = c + -1c

Combine like terms: 10c + -1c = 9c
9c = c + -1c

Combine like terms: c + -1c = 0
9c = 0

Divide each side by '9'.
c = 0

Simplifying
c = 0

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