10(c-6)+4=2-c

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Solution for 10(c-6)+4=2-c equation:



10(c-6)+4=2-c
We move all terms to the left:
10(c-6)+4-(2-c)=0
We add all the numbers together, and all the variables
10(c-6)-(-1c+2)+4=0
We multiply parentheses
10c-(-1c+2)-60+4=0
We get rid of parentheses
10c+1c-2-60+4=0
We add all the numbers together, and all the variables
11c-58=0
We move all terms containing c to the left, all other terms to the right
11c=58
c=58/11
c=5+3/11

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