10(c-6)=290

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Solution for 10(c-6)=290 equation: 



10(c-6)=290

We move all terms to the left:

10(c-6)-(290)=0

We multiply parentheses

10c-60-290=0

We add all the numbers together, and all the variables

10c-350=0

We move all terms containing c to the left, all other terms to the right

10c=350

c=350/10

c=35

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