10(d)+5(d+2)+25(d+2+3)=335

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Solution for 10(d)+5(d+2)+25(d+2+3)=335 equation:


10(d)+5(d+2)+25(d+2+3)=335

We simplify the equation to the form, which is simple to understand
10(d)+5(d+2)+25(d+2+3)=335

Reorder the terms in parentheses
+(+10d)+5*(d+2)+25*(+5+1d)=335

Remove unnecessary parentheses
+10d+5+*(+d+2+)+25+*(+5+1d+)=+335

Reorder the terms in parentheses
+10d+(+5d+10)+25*(+5+1d)=335

Remove unnecessary parentheses
+10d+5d+10+25+*(+5+1d+)=+335

Reorder the terms in parentheses
+10d+5d+10+(+125+25d)=335

Remove unnecessary parentheses
+10d+5d+10+125+25d=+335

We move all terms containing d to the left and all other terms to the right.
+10d+5d+25d=+335-10-125

We simplify left and right side of the equation.
+40d=+200

We divide both sides of the equation by 40 to get d.
d=5

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