10(d+2)-3(2d-5)=45

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Solution for 10(d+2)-3(2d-5)=45 equation: 



10(d+2)-3(2d-5)=45

We move all terms to the left:

10(d+2)-3(2d-5)-(45)=0

We multiply parentheses

10d-6d+20+15-45=0

We add all the numbers together, and all the variables

4d-10=0

We move all terms containing d to the left, all other terms to the right

4d=10

d=10/4

d=2+1/2

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