10(d+4)=6(d-12)

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Solution for 10(d+4)=6(d-12) equation: 



10(d+4)=6(d-12)

We move all terms to the left:

10(d+4)-(6(d-12))=0

We multiply parentheses

10d-(6(d-12))+40=0



We calculate terms in parentheses: -(6(d-12)), so:

6(d-12)

We multiply parentheses

6d-72

Back to the equation:

-(6d-72)



We get rid of parentheses

10d-6d+72+40=0

We add all the numbers together, and all the variables

4d+112=0

We move all terms containing d to the left, all other terms to the right

4d=-112

d=-112/4

d=-28

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