10(d+7)=2(d-2)

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Solution for 10(d+7)=2(d-2) equation: 



10(d+7)=2(d-2)

We move all terms to the left:

10(d+7)-(2(d-2))=0

We multiply parentheses

10d-(2(d-2))+70=0



We calculate terms in parentheses: -(2(d-2)), so:

2(d-2)

We multiply parentheses

2d-4

Back to the equation:

-(2d-4)



We get rid of parentheses

10d-2d+4+70=0

We add all the numbers together, and all the variables

8d+74=0

We move all terms containing d to the left, all other terms to the right

8d=-74

d=-74/8

d=-9+1/4

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