10(h+1)=3(2h+4)-2(-2h+1)

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Solution for 10(h+1)=3(2h+4)-2(-2h+1) equation: 


Simplifying
10(h + 1) = 3(2h + 4) + -2(-2h + 1)

Reorder the terms:
10(1 + h) = 3(2h + 4) + -2(-2h + 1)
(1 * 10 + h * 10) = 3(2h + 4) + -2(-2h + 1)
(10 + 10h) = 3(2h + 4) + -2(-2h + 1)

Reorder the terms:
10 + 10h = 3(4 + 2h) + -2(-2h + 1)
10 + 10h = (4 * 3 + 2h * 3) + -2(-2h + 1)
10 + 10h = (12 + 6h) + -2(-2h + 1)

Reorder the terms:
10 + 10h = 12 + 6h + -2(1 + -2h)
10 + 10h = 12 + 6h + (1 * -2 + -2h * -2)
10 + 10h = 12 + 6h + (-2 + 4h)

Reorder the terms:
10 + 10h = 12 + -2 + 6h + 4h

Combine like terms: 12 + -2 = 10
10 + 10h = 10 + 6h + 4h

Combine like terms: 6h + 4h = 10h
10 + 10h = 10 + 10h

Add '-10' to each side of the equation.
10 + -10 + 10h = 10 + -10 + 10h

Combine like terms: 10 + -10 = 0
0 + 10h = 10 + -10 + 10h
10h = 10 + -10 + 10h

Combine like terms: 10 + -10 = 0
10h = 0 + 10h
10h = 10h

Add '-10h' to each side of the equation.
10h + -10h = 10h + -10h

Combine like terms: 10h + -10h = 0
0 = 10h + -10h

Combine like terms: 10h + -10h = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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