10(h+1)=4(h+4)+12.

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Solution for 10(h+1)=4(h+4)+12. equation: 



10(h+1)=4(h+4)+12.

We move all terms to the left:

10(h+1)-(4(h+4)+12.)=0

We multiply parentheses

10h-(4(h+4)+12.)+10=0



We calculate terms in parentheses: -(4(h+4)+12.), so:

4(h+4)+12.

We add all the numbers together, and all the variables

4(h+4)+12

We multiply parentheses

4h+16+12

We add all the numbers together, and all the variables

4h+28

Back to the equation:

-(4h+28)



We get rid of parentheses

10h-4h-28+10=0

We add all the numbers together, and all the variables

6h-18=0

We move all terms containing h to the left, all other terms to the right

6h=18

h=18/6

h=3

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