10(n+52)=-80

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Solution for 10(n+52)=-80 equation: 



10(n+52)=-80

We move all terms to the left:

10(n+52)-(-80)=0

We add all the numbers together, and all the variables

10(n+52)+80=0

We multiply parentheses

10n+520+80=0

We add all the numbers together, and all the variables

10n+600=0

We move all terms containing n to the left, all other terms to the right

10n=-600

n=-600/10

n=-60

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