10(n-2)-2(n-3)=3(2n+1)+1

Solution for 10(n-2)-2(n-3)=3(2n+1)+1 equation:

10(n-2)-2(n-3)=3(2n+1)+1

We move all terms to the left:

10(n-2)-2(n-3)-(3(2n+1)+1)=0

We multiply parentheses

10n-2n-(3(2n+1)+1)-20+6=0


We calculate terms in parentheses: -(3(2n+1)+1), so:

3(2n+1)+1

We multiply parentheses

6n+3+1

We add all the numbers together, and all the variables

6n+4

Back to the equation:

-(6n+4)


We add all the numbers together, and all the variables

8n-(6n+4)-14=0

We get rid of parentheses

8n-6n-4-14=0

We add all the numbers together, and all the variables

2n-18=0

We move all terms containing n to the left, all other terms to the right

2n=18

n=18/2

n=9