10(r-2)+2=3(r+3)+8

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Solution for 10(r-2)+2=3(r+3)+8 equation: 



10(r-2)+2=3(r+3)+8

We move all terms to the left:

10(r-2)+2-(3(r+3)+8)=0

We multiply parentheses

10r-(3(r+3)+8)-20+2=0



We calculate terms in parentheses: -(3(r+3)+8), so:

3(r+3)+8

We multiply parentheses

3r+9+8

We add all the numbers together, and all the variables

3r+17

Back to the equation:

-(3r+17)



We add all the numbers together, and all the variables

10r-(3r+17)-18=0

We get rid of parentheses

10r-3r-17-18=0

We add all the numbers together, and all the variables

7r-35=0

We move all terms containing r to the left, all other terms to the right

7r=35

r=35/7

r=5

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