10(r-8)=5(r+4)+10

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Solution for 10(r-8)=5(r+4)+10 equation: 



10(r-8)=5(r+4)+10

We move all terms to the left:

10(r-8)-(5(r+4)+10)=0

We multiply parentheses

10r-(5(r+4)+10)-80=0



We calculate terms in parentheses: -(5(r+4)+10), so:

5(r+4)+10

We multiply parentheses

5r+20+10

We add all the numbers together, and all the variables

5r+30

Back to the equation:

-(5r+30)



We get rid of parentheses

10r-5r-30-80=0

We add all the numbers together, and all the variables

5r-110=0

We move all terms containing r to the left, all other terms to the right

5r=110

r=110/5

r=22

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