10(s-2)-7=3(s+7)+1

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Solution for 10(s-2)-7=3(s+7)+1 equation: 



10(s-2)-7=3(s+7)+1

We move all terms to the left:

10(s-2)-7-(3(s+7)+1)=0

We multiply parentheses

10s-(3(s+7)+1)-20-7=0



We calculate terms in parentheses: -(3(s+7)+1), so:

3(s+7)+1

We multiply parentheses

3s+21+1

We add all the numbers together, and all the variables

3s+22

Back to the equation:

-(3s+22)



We add all the numbers together, and all the variables

10s-(3s+22)-27=0

We get rid of parentheses

10s-3s-22-27=0

We add all the numbers together, and all the variables

7s-49=0

We move all terms containing s to the left, all other terms to the right

7s=49

s=49/7

s=7

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