10(t-2)+4t=7(2t+5)-12

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Solution for 10(t-2)+4t=7(2t+5)-12 equation:


10(t-2)+4t=7(2t+5)-12

We simplify the equation to the form, which is simple to understand
10(t-2)+4t=7(2t+5)-12

Reorder the terms in parentheses
+(+10t-20)+4t=7*(2t+5)-12

Remove unnecessary parentheses
+10t-20+4t=+7+*(+2t+5+)-12

Reorder the terms in parentheses
+10t-20+4t=+(+14t+35)-12

Remove unnecessary parentheses
+10t-20+4t=+14t+35-12

We move all terms containing t to the left and all other terms to the right.
+10t+4t-14t=+35-12+20

We simplify left and right side of the equation.
t=+43

0=43

The left and right sides are not equal, therefore there is no solution. This equation is invalid.

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