10(t-2)+8t=6(3t+4)-10

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Solution for 10(t-2)+8t=6(3t+4)-10 equation: 



10(t-2)+8t=6(3t+4)-10

We move all terms to the left:

10(t-2)+8t-(6(3t+4)-10)=0

We add all the numbers together, and all the variables

8t+10(t-2)-(6(3t+4)-10)=0

We multiply parentheses

8t+10t-(6(3t+4)-10)-20=0



We calculate terms in parentheses: -(6(3t+4)-10), so:

6(3t+4)-10

We multiply parentheses

18t+24-10

We add all the numbers together, and all the variables

18t+14

Back to the equation:

-(18t+14)



We add all the numbers together, and all the variables

18t-(18t+14)-20=0

We get rid of parentheses

18t-18t-14-20=0

We add all the numbers together, and all the variables

-34!=0

There is no solution for this equation

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