10(t-4)+8t=6(3t+4)-8

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Solution for 10(t-4)+8t=6(3t+4)-8 equation: 



10(t-4)+8t=6(3t+4)-8

We move all terms to the left:

10(t-4)+8t-(6(3t+4)-8)=0

We add all the numbers together, and all the variables

8t+10(t-4)-(6(3t+4)-8)=0

We multiply parentheses

8t+10t-(6(3t+4)-8)-40=0



We calculate terms in parentheses: -(6(3t+4)-8), so:

6(3t+4)-8

We multiply parentheses

18t+24-8

We add all the numbers together, and all the variables

18t+16

Back to the equation:

-(18t+16)



We add all the numbers together, and all the variables

18t-(18t+16)-40=0

We get rid of parentheses

18t-18t-16-40=0

We add all the numbers together, and all the variables

-56!=0

There is no solution for this equation

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