10(t-4)=5(2t-8)

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Solution for 10(t-4)=5(2t-8) equation:


Simplifying
10(t + -4) = 5(2t + -8)

Reorder the terms:
10(-4 + t) = 5(2t + -8)
(-4 * 10 + t * 10) = 5(2t + -8)
(-40 + 10t) = 5(2t + -8)

Reorder the terms:
-40 + 10t = 5(-8 + 2t)
-40 + 10t = (-8 * 5 + 2t * 5)
-40 + 10t = (-40 + 10t)

Add '40' to each side of the equation.
-40 + 40 + 10t = -40 + 40 + 10t

Combine like terms: -40 + 40 = 0
0 + 10t = -40 + 40 + 10t
10t = -40 + 40 + 10t

Combine like terms: -40 + 40 = 0
10t = 0 + 10t
10t = 10t

Add '-10t' to each side of the equation.
10t + -10t = 10t + -10t

Combine like terms: 10t + -10t = 0
0 = 10t + -10t

Combine like terms: 10t + -10t = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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