10(t-5)+8t=6(3t+3)-12

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Solution for 10(t-5)+8t=6(3t+3)-12 equation: 



10(t-5)+8t=6(3t+3)-12

We move all terms to the left:

10(t-5)+8t-(6(3t+3)-12)=0

We add all the numbers together, and all the variables

8t+10(t-5)-(6(3t+3)-12)=0

We multiply parentheses

8t+10t-(6(3t+3)-12)-50=0



We calculate terms in parentheses: -(6(3t+3)-12), so:

6(3t+3)-12

We multiply parentheses

18t+18-12

We add all the numbers together, and all the variables

18t+6

Back to the equation:

-(18t+6)



We add all the numbers together, and all the variables

18t-(18t+6)-50=0

We get rid of parentheses

18t-18t-6-50=0

We add all the numbers together, and all the variables

-56!=0

There is no solution for this equation

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