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10(v+1)-4v=2(3v+2)-8
We move all terms to the left:
10(v+1)-4v-(2(3v+2)-8)=0
We add all the numbers together, and all the variables
-4v+10(v+1)-(2(3v+2)-8)=0
We multiply parentheses
-4v+10v-(2(3v+2)-8)+10=0
We calculate terms in parentheses: -(2(3v+2)-8), so:We add all the numbers together, and all the variables
2(3v+2)-8
We multiply parentheses
6v+4-8
We add all the numbers together, and all the variables
6v-4
Back to the equation:
-(6v-4)
6v-(6v-4)+10=0
We get rid of parentheses
6v-6v+4+10=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation
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