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10(v+2)-4v=3(2v+3)-13
We move all terms to the left:
10(v+2)-4v-(3(2v+3)-13)=0
We add all the numbers together, and all the variables
-4v+10(v+2)-(3(2v+3)-13)=0
We multiply parentheses
-4v+10v-(3(2v+3)-13)+20=0
We calculate terms in parentheses: -(3(2v+3)-13), so:We add all the numbers together, and all the variables
3(2v+3)-13
We multiply parentheses
6v+9-13
We add all the numbers together, and all the variables
6v-4
Back to the equation:
-(6v-4)
6v-(6v-4)+20=0
We get rid of parentheses
6v-6v+4+20=0
We add all the numbers together, and all the variables
24!=0
There is no solution for this equation
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