10(v-2)-8=2(2v+11)+4

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Solution for 10(v-2)-8=2(2v+11)+4 equation: 



10(v-2)-8=2(2v+11)+4

We move all terms to the left:

10(v-2)-8-(2(2v+11)+4)=0

We multiply parentheses

10v-(2(2v+11)+4)-20-8=0



We calculate terms in parentheses: -(2(2v+11)+4), so:

2(2v+11)+4

We multiply parentheses

4v+22+4

We add all the numbers together, and all the variables

4v+26

Back to the equation:

-(4v+26)



We add all the numbers together, and all the variables

10v-(4v+26)-28=0

We get rid of parentheses

10v-4v-26-28=0

We add all the numbers together, and all the variables

6v-54=0

We move all terms containing v to the left, all other terms to the right

6v=54

v=54/6

v=9

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