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10(x+1)-6(2x+1)=15
We move all terms to the left:
10(x+1)-6(2x+1)-(15)=0
We multiply parentheses
10x-12x+10-6-15=0
We add all the numbers together, and all the variables
-2x-11=0
We move all terms containing x to the left, all other terms to the right
-2x=11
x=11/-2
x=-5+1/2
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