10(x+1)=7(x-4)

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Solution for 10(x+1)=7(x-4) equation:



10(x+1)=7(x-4)
We move all terms to the left:
10(x+1)-(7(x-4))=0
We multiply parentheses
10x-(7(x-4))+10=0
We calculate terms in parentheses: -(7(x-4)), so:
7(x-4)
We multiply parentheses
7x-28
Back to the equation:
-(7x-28)
We get rid of parentheses
10x-7x+28+10=0
We add all the numbers together, and all the variables
3x+38=0
We move all terms containing x to the left, all other terms to the right
3x=-38
x=-38/3
x=-12+2/3

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