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10(x+1)=7(x/4)
We move all terms to the left:
10(x+1)-(7(x/4))=0
We add all the numbers together, and all the variables
10(x+1)-(7(+x/4))=0
We multiply parentheses
10x-(7(+x/4))+10=0
We multiply all the terms by the denominator
10x*4))-(7(+x+10*4))=0
We add all the numbers together, and all the variables
10x*4))-(7(x+40))=0
We add all the numbers together, and all the variables
10x*4))-(7(x=0
Wy multiply elements
40x^2=0
a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{80}=0$
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