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10(x+12)(x-7)=0
We multiply parentheses ..
10(+x^2-7x+12x-84)=0
We multiply parentheses
10x^2-70x+120x-840=0
We add all the numbers together, and all the variables
10x^2+50x-840=0
a = 10; b = 50; c = -840;
Δ = b2-4ac
Δ = 502-4·10·(-840)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36100}=190$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-190}{2*10}=\frac{-240}{20} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+190}{2*10}=\frac{140}{20} =7 $
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