10(x+2)+3(x-1)=9(x+2

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Solution for 10(x+2)+3(x-1)=9(x+2 equation: 



10(x+2)+3(x-1)=9(x+2

We move all terms to the left:

10(x+2)+3(x-1)-(9(x+2)=0

We multiply parentheses

10x+3x-(9(x+2)+20-3=0

We add all the numbers together, and all the variables

13x-(9(x+2)+20-3=0

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