10(x+2)-3x=5(6-x)+2

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Solution for 10(x+2)-3x=5(6-x)+2 equation: 



10(x+2)-3x=5(6-x)+2

We move all terms to the left:

10(x+2)-3x-(5(6-x)+2)=0

We add all the numbers together, and all the variables

10(x+2)-3x-(5(-1x+6)+2)=0

We add all the numbers together, and all the variables

-3x+10(x+2)-(5(-1x+6)+2)=0

We multiply parentheses

-3x+10x-(5(-1x+6)+2)+20=0



We calculate terms in parentheses: -(5(-1x+6)+2), so:

5(-1x+6)+2

We multiply parentheses

-5x+30+2

We add all the numbers together, and all the variables

-5x+32

Back to the equation:

-(-5x+32)



We add all the numbers together, and all the variables

7x-(-5x+32)+20=0

We get rid of parentheses

7x+5x-32+20=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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