10(x+2)-8x=48

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Solution for 10(x+2)-8x=48 equation: 



10(x+2)-8x=48

We move all terms to the left:

10(x+2)-8x-(48)=0

We add all the numbers together, and all the variables

-8x+10(x+2)-48=0

We multiply parentheses

-8x+10x+20-48=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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