10(x+2)/7=2x-4

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Solution for 10(x+2)/7=2x-4 equation:



10(x+2)/7=2x-4
We move all terms to the left:
10(x+2)/7-(2x-4)=0
We get rid of parentheses
10(x+2)/7-2x+4=0
We multiply all the terms by the denominator
10(x+2)-2x*7+4*7=0
We add all the numbers together, and all the variables
10(x+2)-2x*7+28=0
We multiply parentheses
10x-2x*7+20+28=0
Wy multiply elements
10x-14x+20+28=0
We add all the numbers together, and all the variables
-4x+48=0
We move all terms containing x to the left, all other terms to the right
-4x=-48
x=-48/-4
x=+12

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