10(x+2)=5(x-4)

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Solution for 10(x+2)=5(x-4) equation: 



10(x+2)=5(x-4)

We move all terms to the left:

10(x+2)-(5(x-4))=0

We multiply parentheses

10x-(5(x-4))+20=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We get rid of parentheses

10x-5x+20+20=0

We add all the numbers together, and all the variables

5x+40=0

We move all terms containing x to the left, all other terms to the right

5x=-40

x=-40/5

x=-8

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