10(x+2)=6(x+2)+4(x+2)

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Solution for 10(x+2)=6(x+2)+4(x+2) equation: 



10(x+2)=6(x+2)+4(x+2)

We move all terms to the left:

10(x+2)-(6(x+2)+4(x+2))=0

We multiply parentheses

10x-(6(x+2)+4(x+2))+20=0



We calculate terms in parentheses: -(6(x+2)+4(x+2)), so:

6(x+2)+4(x+2)

We multiply parentheses

6x+4x+12+8

We add all the numbers together, and all the variables

10x+20

Back to the equation:

-(10x+20)



We get rid of parentheses

10x-10x-20+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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