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10(x+3)-(9-x-4)=x-5+3
We move all terms to the left:
10(x+3)-(9-x-4)-(x-5+3)=0
We add all the numbers together, and all the variables
10(x+3)-(-1x+5)-(x-2)=0
We multiply parentheses
10x-(-1x+5)-(x-2)+30=0
We get rid of parentheses
10x+1x-x-5+2+30=0
We add all the numbers together, and all the variables
10x+27=0
We move all terms containing x to the left, all other terms to the right
10x=-27
x=-27/10
x=-2+7/10
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