10(x+3)-5=2x+8(1+x)

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Solution for 10(x+3)-5=2x+8(1+x) equation: 



10(x+3)-5=2x+8(1+x)

We move all terms to the left:

10(x+3)-5-(2x+8(1+x))=0

We add all the numbers together, and all the variables

10(x+3)-(2x+8(x+1))-5=0

We multiply parentheses

10x-(2x+8(x+1))+30-5=0



We calculate terms in parentheses: -(2x+8(x+1)), so:

2x+8(x+1)

We multiply parentheses

2x+8x+8

We add all the numbers together, and all the variables

10x+8

Back to the equation:

-(10x+8)



We add all the numbers together, and all the variables

10x-(10x+8)+25=0

We get rid of parentheses

10x-10x-8+25=0

We add all the numbers together, and all the variables

17!=0

There is no solution for this equation

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