10(x+3)=12(x-2)+43

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Solution for 10(x+3)=12(x-2)+43 equation: 



10(x+3)=12(x-2)+43

We move all terms to the left:

10(x+3)-(12(x-2)+43)=0

We multiply parentheses

10x-(12(x-2)+43)+30=0



We calculate terms in parentheses: -(12(x-2)+43), so:

12(x-2)+43

We multiply parentheses

12x-24+43

We add all the numbers together, and all the variables

12x+19

Back to the equation:

-(12x+19)



We get rid of parentheses

10x-12x-19+30=0

We add all the numbers together, and all the variables

-2x+11=0

We move all terms containing x to the left, all other terms to the right

-2x=-11

x=-11/-2

x=5+1/2

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