10(x+3)=6(2x+12)

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Solution for 10(x+3)=6(2x+12) equation: 



10(x+3)=6(2x+12)

We move all terms to the left:

10(x+3)-(6(2x+12))=0

We multiply parentheses

10x-(6(2x+12))+30=0



We calculate terms in parentheses: -(6(2x+12)), so:

6(2x+12)

We multiply parentheses

12x+72

Back to the equation:

-(12x+72)



We get rid of parentheses

10x-12x-72+30=0

We add all the numbers together, and all the variables

-2x-42=0

We move all terms containing x to the left, all other terms to the right

-2x=42

x=42/-2

x=-21

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