10(x+3)=6(2x+12)

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Solution for 10(x+3)=6(2x+12) equation:



10(x+3)=6(2x+12)
We move all terms to the left:
10(x+3)-(6(2x+12))=0
We multiply parentheses
10x-(6(2x+12))+30=0
We calculate terms in parentheses: -(6(2x+12)), so:
6(2x+12)
We multiply parentheses
12x+72
Back to the equation:
-(12x+72)
We get rid of parentheses
10x-12x-72+30=0
We add all the numbers together, and all the variables
-2x-42=0
We move all terms containing x to the left, all other terms to the right
-2x=42
x=42/-2
x=-21

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