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10(x+3)=6(2x+5)-2x
We move all terms to the left:
10(x+3)-(6(2x+5)-2x)=0
We multiply parentheses
10x-(6(2x+5)-2x)+30=0
We calculate terms in parentheses: -(6(2x+5)-2x), so:We get rid of parentheses
6(2x+5)-2x
We add all the numbers together, and all the variables
-2x+6(2x+5)
We multiply parentheses
-2x+12x+30
We add all the numbers together, and all the variables
10x+30
Back to the equation:
-(10x+30)
10x-10x-30+30=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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