10(x+3)=7(x+9)-21

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Solution for 10(x+3)=7(x+9)-21 equation: 



10(x+3)=7(x+9)-21

We move all terms to the left:

10(x+3)-(7(x+9)-21)=0

We multiply parentheses

10x-(7(x+9)-21)+30=0



We calculate terms in parentheses: -(7(x+9)-21), so:

7(x+9)-21

We multiply parentheses

7x+63-21

We add all the numbers together, and all the variables

7x+42

Back to the equation:

-(7x+42)



We get rid of parentheses

10x-7x-42+30=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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