10(x+4)-4(x-2)=3(x-1)-2(3-x)

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Solution for 10(x+4)-4(x-2)=3(x-1)-2(3-x) equation: 



10(x+4)-4(x-2)=3(x-1)-2(3-x)

We move all terms to the left:

10(x+4)-4(x-2)-(3(x-1)-2(3-x))=0

We add all the numbers together, and all the variables

10(x+4)-4(x-2)-(3(x-1)-2(-1x+3))=0

We multiply parentheses

10x-4x-(3(x-1)-2(-1x+3))+40+8=0



We calculate terms in parentheses: -(3(x-1)-2(-1x+3)), so:

3(x-1)-2(-1x+3)

We multiply parentheses

3x+2x-3-6

We add all the numbers together, and all the variables

5x-9

Back to the equation:

-(5x-9)



We add all the numbers together, and all the variables

6x-(5x-9)+48=0

We get rid of parentheses

6x-5x+9+48=0

We add all the numbers together, and all the variables

x+57=0

We move all terms containing x to the left, all other terms to the right

x=-57

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