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10(x+4)-9(x-3)=8(x+3
We move all terms to the left:
10(x+4)-9(x-3)-(8(x+3)=0
We multiply parentheses
10x-9x-(8(x+3)+40+27=0
We add all the numbers together, and all the variables
x-(8(x+3)+40+27=0
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